JEE MAIN - Physics (2022 - 24th June Morning Shift - No. 15)
Nucleus A is having mass number 220 and its binding energy per nucleon is 5.6 MeV. It splits in two fragments 'B' and 'C' of mass numbers 105 and 115. The binding energy of nucleons in 'B' and 'C' is 6.4 MeV per nucleon. The energy Q released per fission will be :
0.8 MeV
275 MeV
220 MeV
176 MeV
Wyjaśnienie
220A $$\to$$ 105B + 115C
$$\Rightarrow$$ Q = [105 $$\times$$ 6.4 + 115 $$\times$$ 6.4] $$-$$ [220 $$\times$$ 5.6] MeV
$$\Rightarrow$$ Q = 176 MeV